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How to debug a script launched with exec()


Joined: 16 Feb 2010
Posts: 5
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Hi

My PHP script launches another PHP script like this:

Code:
exec("/usr/bin/php -q /var/www/shop/includes/crons/cron4.php >/dev/null &");


While debugging the script, how can I debug the script launched from it?

Thanks for your help.
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How to debug a script launched with exec()
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