Site Admin
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then you know what to do
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_________________ The PHP IDE team |
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Because I can't search among what other users have previously asked on the same subject. And also because I can't expect getting comments from other users. Gingko |
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By the way, I just upgraded to PhpED 19.1.0.19101 (from 19.0.0.19037) right now. Since then, DebugBreak('1@xxx.xxx.xxx.xxx') gives me an immediate segmentation error. (whereas it worked before, and whereas DebugBreak() alone still works properly). And yes, I upgraded also the dbg-php-5.6.so module, and restarted the web server. On Linux Debian 7 Wheezy x86. I just filed a support request. Gingko |
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Site Admin
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Can you try the following?
$ DBGSESSID='1@xxx.xxx.xxx.xxx' /path/to/php /path/to/your/script.php As of DebugBreak(), right, there were recent changes in PHP API introduced with version 7.3 -- they dropped the interfaces debugger used to parse parameters passed by scripts, so I had to rewrite some parts and these changes cause problems in php core under some platforms. I'll update debugger soon with the fix. |
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_________________ The PHP IDE team |
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This doesn't looks like an allowable syntax that I could write as a function argument for DebugBreak(). … but anyway, if the DebugBreak() arguments no longer works, I'm afraid that there could no longer be any place to write it either. Gingko |
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Site Admin
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this is common syntax for Linux console -- it's where you're running your scripts. Syntax is perfectly valid for bash driven shell. If you're running a shell that uses syntax different than bash, you need to check with manual on how to set variables.
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_________________ The PHP IDE team |
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Anyway if you write it in a Linux console, there shouldn't be a “$” sign at the beginning. Gingko |
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Site Admin
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This is a common notation: $ indicates that you want to run it using regular user account, whereas # would mean -- you need root to run this.
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_________________ The PHP IDE team |
Debugging requests from one host to another |
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