PHP IDE :: NuSphere Forums :: View topic - PhpEd Debugger show variable empty value

Posted: Fri Jan 07, 2011 7:16 am

Code:

<?php

// show SELECT result as HTML table
function show_table($result) {
if(!$result) {
echo "<p>No valid query result.</p>\n";
return;
}

if($result->num_rows>0 && $result->field_count>0) {
echo "<table>";

// column headings
echo "<tr>";
// tworzy zmienn? $meta ktora sie potem juz nie zmienia
foreach($result->fetch_fields() as $meta)
printf("<th>%s</th>", htmlspecialchars($meta->name));
echo "</tr>\n";

// content
// row fetch row
// tworzy $row
while($row = $result->fetch_row()) {
echo "<tr>";
// wartosc z $row idzie do $col
foreach($row as $col)
printf("<td>%s</td>", htmlspecialchars($col));
echo "</tr>\n";
}
echo "</table>\n";
}
}

require_once 'password.php';

// connect to MySQL
$mysqli = new mysqli($mysqlhost, $mysqluser, $mysqlpasswd, $mysqldb);
if(mysqli_connect_errno()) {
echo "<p>Sorry, no connection! ", mysqli_connect_error(), "</p>\n";
exit();
}

// show SELECT result with show_table
//$result przestaje byc NULL - przyjmuje pust? wartosc
if($result = $mysqli->query("SELECT * FROM titles")) {
show_table($result);
$result->close();
}

// disconnect
$mysqli->close();

?>
</body></html>

<?php

?>