Hi all,

I'm a newbie on Phped (using 5.0). I tried to debug some existing code as to learn how to enhance it. But, the code expects to be run from "command line". The code breaks at the following test:

if ( isset( $_SERVER ) && array_key_exists( 'REQUEST_METHOD', $_SERVER ) ) {
print "This script must be run from the command line\n";
exit();
}

I tried to search in the help for any hints about how to mimic command line, but I couldn't find any. I'd like to know if there's a way to mimic running from command line while debugging, /without/ having to uncomment this check?

Any hints?

Regards,

// Rolf Lampa

Does anyone know if the debugger can be brought to respond an stop at break points under the following conditions:

1. Start a php script from Win32 XP command line (...>"php somescript.php" )
2. Breakpoints in somescript.php are set from the PHP IDE (5.5)
3. Using xampplite

Should this be possible to debug with the option "3rd Party Webserver"? ( I have tried hard all day (and googled & read the help files) but it seems like I can stop and step only if I start from the IDE).

// Rolf Lampa